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2 2 g x d x 10, Solving Large Scale Nonlinear by a New Numerical Method, $\int_{-\infty}^{\infty}f(x)\overline {g(x)}dx = \frac{1}{2\pi}\int_{-\infty}^{\infty} \hat{f}(\mu)\overline{\hat{g}(\mu)}d\mu.$ - Mathematics Stack Exchange

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$SOLVED:Given \int_{-2}^{2} g(x) d x=8 and g(x) d (a) \int_{-2}^{0} g(x) d x (b) \int_{2}^{-2} g(x) d x (c) \int_{0}^{-2} 5 g(x) d x (d) \int_{-2}^{2} 2 g(x) d x$ SOLVED:Given \int_{-2}^{2} g(x) d x=8 and g(x) d (a) \int_{-2}^{0} g(x) d x (b) \int_{2}^{-2} g(x) d x (c) \int_{0}^{-2} 5 g(x) d x (d) \int_{-2}^{2} 2 g(x) d x
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$Question 15. $ \int \left( x { 2 } + 1 \right) \log x d x $ Solvtion Let $ I \left( ^ { 2 } + 1 \$ Question 15. \( \int \left( x { 2 } + 1 \right) \log x d x $ Solvtion Let \( I \left( ^ { 2 } + 1 \
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$SOLVED:Given \int_{-2}^{2} g(x) d x=8 and g(x) d (a) \int_{-2}^{0} g(x) d x (b) \int_{2}^{-2} g(x) d x (c) \int_{0}^{-2} 5 g(x) d x (d) \int_{-2}^{2} 2 g(x) d x$ SOLVED:Given \int_{-2}^{2} g(x) d x=8 and g(x) d (a) \int_{-2}^{0} g(x) d x (b) \int_{2}^{-2} g(x) d x (c) \int_{0}^{-2} 5 g(x) d x (d) \int_{-2}^{2} 2 g(x) d x
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$$\int_{-\infty}^{\infty}f(x)\overline {g(x)}dx = \frac{1}{2\pi}\int_{-\infty}^{\infty} \hat{f}(\mu)\overline{\hat{g}(\mu)}d\mu.$ - Mathematics Stack Exchange$ $\int_{-\infty}^{\infty}f(x)\overline {g(x)}dx = \frac{1}{2\pi}\int_{-\infty}^{\infty} \hat{f}(\mu)\overline{\hat{g}(\mu)}d\mu.$ - Mathematics Stack Exchange
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